**Latest TCS Placement Papers Fully Solved 2014**

Dear Job Seekers, as you know we (www.allindiajobs.in) always tries to help job aspirants in all the possible ways to reach their goal. So recently we have collected the placement papers of different IT and non-IT companies through different sources which helps you guys to clear written tests conducted by MNC companies. Here is the latest placement paper of Tata Consultancy Services.

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**TCS Placement Paper 2014 Part-1:****1) A power unit is there by the bank of a river of 900 meters. A cable is made from power unit to power a plant opposite to that of the river of 2000mts. The cost of the cable below water is Rs. 5/- per meter and cost of cable on the bank is Rs. 4/- per meter. Then find out the amount to be invested to connect those two stations?**

__Explanation:__

Required length of wire = 2000 mts cost of cable below water = 900 * 5 = 4500 cost of cable on the bank of river= (2000 – 900) * 4 = 4400 Total cost = 4500 + 4400 = 8900.

**2) A farmer had 20 hens. All but 2 died. How many hens are still alive?**

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__Explanation:__

“All but 2” means 2. So, all but 2 died means that there are only two hens are alive and others were dead. So, the answer is 2.

**3) At this series: 7, 10, 8, 11, 9, 12… What number should come next?**

__Explanation:__

This is a simple alternating addition and subtraction series. In the first pattern, 3 are added; in the second, 2 are subtracted.

**4) A college has 10 basketball players. A 5-member team and a captain will be selected out of these 10 players. How many different selections can be made?**

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__Explanation:__

We can select the 5 member team out of the 10 in 10C5 ways = 252 ways. The captain can be selected from amongst the remaining 5 players in 5 ways. Therefore, total ways the selection of 5 players and a captain can be made = 252*5 = 1260.

**5) There are 3 gentlemen in a meeting: Mr. Yellow, Mr. Green and Mr. Brown. They are wearing yellow, green and brown ties. Mr. Yellow says: “Did you notice that the colors of our ties are different from our names?” The person who is wearing the green tie says, “Yes, you are right!” Do you know Brown is wearing what colour of tie?**

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__Explanation:__

We know that Mr. Yellow was not wearing a yellow tie because of his statement. He also was not wearing the green tie because the one wearing the green tie agreed to his statement. Therefore, Mr. Yellow was wearing a brown tie. Mr. Green was wearing a yellow tie. And Mr. Brown was wearing the green tie.

**6) g[0]=1,g[1]=-1,g[n]=2*g[n-1]-3*g[n-2] then calculate g[4]= ?**

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__Explanation:__

From the given function g[n] =2*g [n-1]-3*g [n-2] put values of n as first 2 then 3, then 4 and you will get the answer. G[2] = 2*g[1]-3*g[0]=-2-3 =-5 , G[3]=2*g[2]-3*g[1] =2*(-5)-3*(-1)=-7, G [4] =2*g[3]-3*g[2]=2*(-7)-3*(-5) =1

**7) Ten years ago X was half of Y. If the ratio of their present ages is 3:4, what will be the total of their present ages?**

__Explanation:__

Let X’s age 10 years ago = x years. Then, Y’s age 10 years ago = 2x years. (x + 10)/ (2x + 10) = 3/4 => 4 (x + 10) = 3 (2x + 10) x = 5 Total of their present ages = (x + 10 + 2x + 10) = 3x + 20 = 15 + 20 = 35 years.

**8) A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:**

__Answer:__120KMPH

**9) In a circular racetrack of length 100 m, three persons A, B and C start together. A and B start in the same direction at speeds of 10 m/s and 8 m/s respectively. While C runs in the opposite at 15 m/s. When will all the three meet for the first time after the start?**

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__Explanation:__

Since the track is a circular track A and B will meet every 50 seconds. i.e. 100 / (10-8). Since it is a multiple of 50 they will be meeting at the starting point every 50 Seconds. If you multiply 15 x 50 you will get 750 and after the second 50 it will be 1500. All of them will meet at the starting point after 100s

**10) A class of 100 students. 24 of them are girls and 32 are not. Which base am I using?**

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__Explanation:__

Let the base be X. Therefore (X*X + X*0 + 0) = (2*X +4) + (3*X + 2), X * X = 5 * X + 6, X * X – 5 * X -6 = 0, (X- 6) (X+1) = 0 Therefore base is 6.

**11) Siva, Sathish, Amar and Praveen are playing cards. Amar is to the right of Sathish, who is to the right of Siva. Who is to the right of Amar?**

__Answer:__Praveen

**12) Ferrari is leading car manufacturer. Ferrari S.P.A. is an Italian sports car. It has enjoyed great success. If Mohan’s Ferrari is 3 times faster than his old MERCEDES which gave him 35 km/ph if Mohan travelled 490 km in his Ferrari the how much time in hours he took?**

__Explanation:__

Time = (Distance/Speed) = (490/35) Therefore the total time = time/3 = (490/35)/3 = 4.6666 Approximately 4.7

**13) My flight takes off at 2 AM from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N 70W. What is the local time when my plane landed?**

__Explanation:__

Total change in degrees in east-west direction = 70 + 10 degrees =80 degrees, Time change due to the change in Longitude = 80*4 = 320 minutes = 5 hrs 20 min. According to the person the time would have been = 2 am + 10 hrs = 12 am. But according to the local time the time would be = 12 – 5.20 = 6 .40am

**14) A class of 25 students took a science test. 10 students had an average (arithmetic mean) score of 80. The other students had an average score of 60. What is the average score of the whole class?**

__Explanation:__

80 × 10 + 60 × 15 = 800 + 900 = 1700 Total number of students = 25 Average weight = 1700/25 The average score of the whole class is 68.

**15) The cost of one pencil, two pens and four erasers is Rs.22 while the cost of five pencils, four pens and two erasers is Rs.32. How much will three pencils, three pens and three erasers cost?**

__Explanation:__

x + 2y + 4z = 22 ——–>1 5x + 4y + 2z = 32 ——->2 multiply eqn (2) by 2 and substract from eqn(1) dividing by 3 we get 3x + 2y = 14———>3 multiplying eqn (1) by 5 and subtracting eqn (2) then divide by 6 we get y + 3z = 13———->4 Adding eqn (3) and (4) we get 3x + 3y +3z = 27

**16) A is 20 percent more efficient than B. If the two persons can complete a piece of work in 60 days. In how many days A working alone can complete the work?**

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__Explanation:__

Ratio of time taken by A and B is 1: 1.2 i.e. 5:6 Let the time taken by A be 5x and by B be 6x , 1/5x + 1/ 6x = 1/60 => x =22. Time taken by A = 5 * 22 = 110

**17) On a certain island, 5% of the 10000 inhabitants are one-legged and half of the others go barefooted. What is the least number of Shoes needed in the island?**

__Explanation:__

In any case the one legged people will all require one shoe per head. From the remaining, half will go barefooted and therefore they need no shoes. And the rest will need two shoes per head. And this works out at one shoe per person for the others. Therefore for the whole population on the average one shoe per head

**18) Look at this series: 14, 28, 20, 40, 32, 64, what number should come next?**

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__Explanation:__

This is an alternating multiplication and subtracting series: First, multiply by 2 and then subtract 8.

**19) Two pipes A and B can fill a tank in 24 min. and 32 min. respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 minutes?**

__Explanation:__

Let B be closed after x minutes. Then, part filled by (A + B) in x min. + part filled by an in (18 – x) min. = 1. X {1/24 + 1/32] + (18 – x) X 1/24 = 1 or 7x/96 + (18 – x)/24 = 1 7x + 4(18 -x) = 96 or x=8 Hence, B must be closed after 8 minutes

**20) At a car park there are 100 vehicles, 60 of which are cars, 30 are vans and the remaining are Lorries. If every vehicle is equally likely to leave, find the probability of car leaving second if either a lorry or van had left first :**

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__Explanation:__

Let S be the sample space and A be the event of a van leaving first. n(S) = 100 n (A) = 30 Probability of a van leaving first: P (A) = 30/100 = 3/10 Let B be the event of a lorry leaving first. n (B) = 100 – 60 – 30 = 10 Probability of a lorry leaving first: P (B) = 10/100 = 1/10 If either a lorry or van had left first, then there would be 99 vehicles remaining, 60 of which are cars. Let T be the sample space and C be the event of a car leaving. n (T) = 99 n(C) = 60 Probability of a car leaving after a lorry or van has left: P(C) = 60/99 = 20/33

**21) A red house is built from red bricks. A blue house is built from blue bricks. A white house is built from white bricks. Then what is a greenhouse made from?**

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__Explanation:__

Glass i.e. Buildings are made of bricks. But a greenhouse is made of glass.

**22) If Rs. 782 be divided into three parts, proportional to 1/2: 2/3: 3/4, then the first part is:**www.allindiajobs.in

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__Explanation:__

Given ratio = 1/2: 2/3:3/4 = 6: 8: 9 1st part = 782*(6/22) = 213.2727.. Approximately equals to 213 www.allindiaobs.in

**23) A man decides to buy a nice horse. He pays $60 for it, and he is very content with the strong animal. After a year, the value of the horse has increased to $70 and he decides to sell the horse . But after a few days later he regrets his decision to sell the beautiful horse, and he buys it again. Unfortunately he has to pay $80 to get it back, so he loses $10. After another year of owing the horse, he finally decides to sell the horse for $90. What is the overall profit the man makes?**

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__Explanation:__

The total expenses are $60 + $80 = $140 and the total earnings are $70 +$90 = $160. The overall profit = $160 – $140 = $ 20

**24) When I become as old as my father is now, I will be 5 times the age of my son. In addition, my son will be 8 yrs older than What I am now. If the sum of my father’s age and my age is equal to100. How old is my son now?**

__Explanation:__

Let us consider the ages of the man, his father & his son is m, f & s respectively. Then according to the problem F=5s………… (i) S + f-m = m+8…….. (ii) F + m = 100……….. (iii) Putting (i) in (iii) we get 5s+m=100…….. (iv) Putting (i) in (ii) we get 6s-2m=8………… (v) Equating (iv) & (v) we get s = 13, f = 65 & m = 36

**25) Nine persons went to the hostel for taking their meals, 8 of them spent Rs.12 each on their meals and ninth spend Rs. 8 more then the average expenditure of all nine. What is the total money spent by them?**

__Explanation:__

Let average expenditure be x Then 8*12 +(x+8) = 9x i.e. 104 + x = 9x; 8x = 104 x = 13 Therefore total money spent is 9x = 9*13 =117

**26) The average of a list of 6 numbers is 20. If we remove one of the numbers, the average of the remaining numbers is 15. What is the number that was removed?**

__Explanation:__

The removed number could be obtained by difference between the sum of original 6 numbers and the sum of remaining 5 numbers i.e. sum of original 6 numbers – sum of remaining 5 numbers sum of original 6 numbers = 20 × 6 = 120 sum of remaining 5 numbers = 15 × 5 = 75 Number removed = sum of original 6 numbers – sum of remaining 5 numbers 120 – 75 = 45

**27) In the word ORGANISATIONAL, if the first and second, third and fourth, fifth and sixth letters are interchanged, what would be the 12th letter from right?**

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__Explanation:__

After interchanging R O A G I N S A T I O N A L 14 13 12 11 10 9 8 7 6 5 4 3 2 1

**28) What are the number of edges, number of vertices and number of faces of a planar cube among the following options?**

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__Explanation:__

**29) We know cube has 6 faces, 12 edges and 8 vertices**

How many alphabets need to be there in a language if one were to make 1 million distinct 3 digit initials using the alphabets of the language?

__Explanation:__

Let the number of required alphabets in the language be ‘n’. Therefore, using ‘n’ alphabets we can form n * n * n = n3 distinct 3 digit initials. These n3 different initials = 1 million i.e. n3 = 106 (1 million = 106) => n3 = (102)3 => n = 102 = 100

**30) Today’s high school students spend too much time thinking about trivial and distracting matters such as fashion. Additionally, they often dress inappropriately on school grounds. Rather than spending time writing another detailed dress policy, we should make school uniforms mandatory. If students were required to wear uniforms, it would increase a sense of community and harmony in our schools and it would instill a sense of discipline in our students. Another positive effect would be that teachers and administrators would no longer have to act as clothing police, freeing them up to focus on more important issues.**

**This paragraph best supports the statement that**

Options:

a) inappropriate clothing leads to failing grades

b) students who wear school uniforms get into better colleges

c) teachers and administrators spend at least 25% of their time enforcing the dress code.

d) school uniforms should be compulsory for high school students

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__Answer: Explanation:__

The support for choice e is in the third sentence “we should make school uniforms mandatory”. There is no evidence provided to support choices a, b, and d. And although we know that teachers and administrators are spending some of their time enforcing dress code, the paragraph does not quantify how much of their time is spent that way, so there is no support for choice c.

**We hope this topic, Latest TCS Placement Papers 2014 Part-1 is useful to you and help you in clearing the TCS written tests. We are going to cover more placement papers in the coming days. So keep visiting our website www.allindiajobs.in**
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