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**Placement papers of Freescale 2016**. Learn and practice the placement papers and interview questions answers of Freescale and find out how much you score before you appear for your next interview and written test.

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**Freescale Placement Papers - Interview Questions:**

**Freescale Placement Papers - Interview Questions:**

**Directions (1-7):Study the following arrangement and answer the questions given below:**

Question 1

R 4 T M 7 W % J 9 5 I # 1 P B 2 T A 3 D $ 6 E N F 8 U H @ How many such vowels are there in the above arrangement, each of which is immediately preceded by a number and not immediately followed by a consonant?

Question 1

R 4 T M 7 W % J 9 5 I # 1 P B 2 T A 3 D $ 6 E N F 8 U H @ How many such vowels are there in the above arrangement, each of which is immediately preceded by a number and not immediately followed by a consonant?

A. None

B. One

C. Two

D. Three

Ans. B

**Question 2**

What should come in place of the question mark (?) in the following series based on the above arrangement? TM% 951 B23 ?

What should come in place of the question mark (?) in the following series based on the above arrangement? TM% 951 B23 ?

A. $EF

B. $6F

C. D$N

D. $E8

Ans. B

**Question 3**

How many such consonants are there in the above arrangement, each of which is neither preceded by a number nor followed by a consonants

How many such consonants are there in the above arrangement, each of which is neither preceded by a number nor followed by a consonants

A. None

B. One

C. Two

D. More than three

Ans. D

**Question 4**

Four of the following five are alike in a certain way based on their positions in the above arrangement and so from a group. Which is the one that does not belong to that group?

Four of the following five are alike in a certain way based on their positions in the above arrangement and so from a group. Which is the one that does not belong to that group?

A. 5J1

B. 7TJ

C. 8N@

D. 32$

Ans. D

**Question 5**

Which of the following is sixth to the right of the fourteenth from the right end?

Which of the following is sixth to the right of the fourteenth from the right end?

A. 5

B. 6

C. I

D. $

Ans. B

**Question 6**

How many such consonants are there in the above arrangement, each of which is immediately followed by a symbol but not immediately preceded by another consonant?

How many such consonants are there in the above arrangement, each of which is immediately followed by a symbol but not immediately preceded by another consonant?

A. None

B. One

C. Two

D. Three

Ans. D

**Question 7**

Which of the following is the eighth to the left of the sixteenth from the left end?

Which of the following is the eighth to the left of the sixteenth from the left end?

A. J

B. E

C. %

D. 6

Ans. A

**Question 8**

For the following, find the next term in the series 6, 24, 60,120, 210

For the following, find the next term in the series 6, 24, 60,120, 210

A. 336

B. 360

C. 330

D. 660

Ans. A

Explanation:

The series is 1.2.3, 2.3.4, 3.4.5, 4.5.6, 5.6.7, ..... ( '.' means product)

**Question 9**

1, 5, 13, 25

1, 5, 13, 25

A. 33

B. 48

C. 41

D. 30

Ans. C

Explanation:

The series is of the form 0^2+1^2, 1^2+2^2,...

**Question 10**

0, 5, 8, 17

0, 5, 8, 17

A. 22

B. 24

C. 25

D. 20

Ans. B

Explanation:

1^2-1, 2^2+1, 3^2-1, 4^2+1, 5^2-1

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**Question 11**

A fast typist can type some matter in 2 hours and a slow typist can type the same in 3 hours. If both type combine, in how much time will they finish?

A fast typist can type some matter in 2 hours and a slow typist can type the same in 3 hours. If both type combine, in how much time will they finish?

A. 2.15 hr

B. 1.12 hr

C. 1.23 hr

D. 1.45 hr

Ans. B

Explanation:

The fast typist's work done in 1 hr = 1/2 The slow typist's work done in 1 hr = 1/3 If they work combine , work done in 1 hr = 1/2+1/3 = 5/6 So, the work will be completed in 6/5 hours. i.e., 1+1/5 hours = 1hr 12 min

**Question 12**

Gavaskar's average in his first 50 innings was 50. After the 51st innings, his average was 51. How many runs did he score in his 51st innings. (supposing that he lost his wicket in his 51st innings)

Gavaskar's average in his first 50 innings was 50. After the 51st innings, his average was 51. How many runs did he score in his 51st innings. (supposing that he lost his wicket in his 51st innings)

A. 101

B. 105

C. 98

D. 112

Ans. A

Explanation:

Total score after 50 innings = 50*50 = 2500 Total score after 51 innings = 51*51 = 2601 So, runs made in the 51st innings = 2601-2500 = 101 If he had not lost his wicket in his 51st innings, he would have scored an unbeaten 50 in his 51st innings.

**Question 13**

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

A. 1 : 3

B. 3 : 2

C. 3 : 4

D. None of these

Ans. B

**Question 14**

What is the sum of all numbers between 100 and 1000 which are divisible by 14 ?

What is the sum of all numbers between 100 and 1000 which are divisible by 14 ?

A. 35393

B. 35392

C. 35352

D. 35329

Ans. B

Explanation:

The number closest to 100 which is greater than 100 and divisible by 14 is 112, which is the first term of the series which has to be summed. The number closest to 1000 which is less than 1000 and divisible by 14 is 994, which is the last term of the series. 112 + 126 + .... + 994 = 14(8+9+ ... + 71) = 35392

**Question 15**

If time at this moment is 9 P.M., what will be the time 23999999992 hours later?

If time at this moment is 9 P.M., what will be the time 23999999992 hours later?

A. 12 am

B. 1 am

C. 1 pm

D. 12 pm

Ans. C

Explanation:

24 billion hours later, it would be 9 P.M. and 8 hours before that it would be 1 P.M.

**Question 16**

I drove 60 km at 30 kmph and then an additional 60 km at 50 kmph. Compute my average speed over my 120 km.

I drove 60 km at 30 kmph and then an additional 60 km at 50 kmph. Compute my average speed over my 120 km.

A. 37 ½ kmph

B. 40 kmph

C. 35 ½ kmph

D. 38 kmph

Ans. A

Explanation:

Time reqd for the first 60 km = 120 min.; Time reqd for the second 60 km = 72 min.; Total time reqd = 192 min Avg speed = (60*120)/192 = 37 1/2

**Question 17**

A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in___ days.

A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in___ days.

A. 15 days

B. 20 days

C. 25 days

D. 30 days

Ans. C

**Question 18**

Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:

Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:

A. 50 m

B. 72 m

C. 80 m

D. 82 m

Ans. A

**Question 19**

The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

A. 15

B. 16

C. 18

D. 25

Ans. B

**Question 20**

At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?

At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?

A. 11

B. 12

C. 10

D. 13

Ans. A

Explanation:

With two people, there is one handshake. With three people, there are three handshakes. With four people, there are six handshakes. In general, with n+1 people, the number of handshakes is the sum of the first n consecutive numbers: 1+2+3+...+n. Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = 66. This is the quadratic equation n2+n-132 = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party

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**Question 22**

The price of the book is marked 20% above the C.P. If the marked price of the book is Rs. 180, then what is the cost of the paper used in a single copy of the book?

The price of the book is marked 20% above the C.P. If the marked price of the book is Rs. 180, then what is the cost of the paper used in a single copy of the book?

A. Rs. 36

B. Rs. 37.50

C. Rs. 42

D. Rs. 44.25

Ans. B

**Question 23**

If 5500 copies are published and the transportation cost on them amounts to Rs. 82500, then what should be the selling price of the book so that the publisher can earn a profit of 25%?

If 5500 copies are published and the transportation cost on them amounts to Rs. 82500, then what should be the selling price of the book so that the publisher can earn a profit of 25%?

A. Rs. 187.50

B. Rs. 191.50

C. Rs. 175

D. Rs. 180

Ans. A

**Question 24**

Royalty on the book is less than the printing cost by:

Royalty on the book is less than the printing cost by:

A. 5%

B. 33(1/5)%

C. 20%

D. 25%

Ans. D

Question 25

What is the central angle of the sector corresponding to the expenditure incurred on Royalty?

Question 25

What is the central angle of the sector corresponding to the expenditure incurred on Royalty?

A. 15º

B. 24º

C. 54º

D. 48º

Ans. C