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**Placement papers of Essar 2016-2017**. Learn and practice the placement papers and interview questions answers of Essar and find out how much you score before you appear for your next interview and written test.

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__Essar Placement Papers - Interview Questions:__

**Question 1**

The fourth proportional to 5, 8, 15 is:

The fourth proportional to 5, 8, 15 is:

A. 18

B. 24

C. 19

D. 20

Ans. B

Explanation:

Let the fourth proportional to 5, 8, 15 be x. Then, 5 : 8 : 15 : x 5x = (8 x 15) x=(8*15)/5=24

**Question 2**

If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?

If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?

A. 2 : 5

B. 3 : 7

C. 5 : 3

D. 7 : 3

Ans. C

Explanation:

Let 40% of A=2/3 B Then,40 A/100=2B/3 => 2A/5=2B/3 => A/B-[2/3 - 5/2]=5/3p A : B = 5 : 3.

**Question 3**

The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?

The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?

A. 3 : 3 : 10

B. 10 : 11 : 20

C. 23:33:60

D. 32 :43:53

Ans. C

Explanation:

Let A = 2k, B = 3k and C = 5k. A's new salary = 115/ 100 of 2k =[115/ 100 x 2k]= 23k/ 10 B's new salary = 110/ 100 of 3k = [110/ 100x 3k] = 33k/ 10 C's new salary = 120/ 100 of 5k = [120/ 100 x 5k] = 6k New ratio = 23k : 33k : 6k = 23 : 33 : 60

**Question 4**

A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?

A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?

A. 3/4

B. 4/7

C. 1/8

D. 3/7

Ans. B

Explanation:

Let number of balls = (6 + 8) = 14. Number of white balls = 8. P (drawing a white ball)=8/14=4/7

**Question 5**

One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card?

One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card?

A. 1/13

B. 3/13

C. 1/4

D. 9/5

Ans. B

Explanation:

Clearly, there are 52 cards, out of which there are 12 face cards. P (getting a face card)=12/52=3/13

**Question 6**

Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:

Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:

A. 3 /20

B. 29/ 34

C. 47/ 100

D. 13 /102

Ans. D

Explanation:

Let S be the sample space. Then, n(S) = 52C2 = 52 * 51/ (2*1)= 1326. Let E = event of getting 1 spade and 1 heart. n(E) = number of ways of choosing 1 spade out of 13 and 1 heart out of 13 = (13C1 x 13C1) = (13 x 13) = 169. P(E) =n (E)/n(S) = 169/ 1326= 13/102

**Question 7**

A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:

A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:

A. 1/ 22

B. 3/ 22

C. 2/ 91

D. 2/ 81

Ans. C

Explanation:

Let S be the sample space. Then, n(S)= number of ways of drawing 3 balls out of 15 = 15C3 = (15 x 14 x 13)/ (3 x 2 x 1) = 455. Let E = event of getting all the 3 red balls. n(E) = 5C3 = 5C2 = (5 x 4)/ (2 x 1)= 10. P(E) = n(E) / n(S)= 10/ 455 = 2/ 91

**Question 8**

A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:

A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:

A. 1 /13

B. 2 /13

C. 1 /26

D. 1 /52

Ans. C

Explanation:

Here, n(S) = 52. Let E = event of getting a queen of club or a king of heart. Then, n(E) = 2. P(E) =n(E)/ n(S)= 2/ 52= 1/ 26

**Question 9**

Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:

Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:

A. 27

B. 33

C. 49

D. 55

Ans. B

Explanation:

Let the numbers be 3x and 5x. Then ,(3x-9)/(5x-9)=12/13 23(3x - 9) = 12(5x - 9) 9x = 99 x = 11. The smaller number = (3 x 11) = 33.

**Question 10**

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?

A. 50

B. 100

C. 150

D. 200

Ans. C

Explanation:

Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively. Then, sum of their values=Rs[(25x/100)+(10*2x)/100+(5*3x)/100]=Rs 60x/100 60x/100=30 =>x=(30*100)/60=50 Hence, the number of 5 p coins = (3 x 50) = 150.

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Question 11

B2CD, _____, BCD4, B5CD, BC6D

Question 11

B2CD, _____, BCD4, B5CD, BC6D

A. B2C2D

B. BC3D

C. B2C3D

D. BCD7

Ans. B

Explanation:

Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order.

**Question 12**

DEF, DEF2, DE2F2, _____, D2E2F3

DEF, DEF2, DE2F2, _____, D2E2F3

A. DEF3

B. D3EF3

C. D2E3F

D. D2E2F2

Ans. D

Explanation:

In this series, the letters remain the same: DEF. The subscript numbers follow this series: 111, 112, 122, 222, 223, 233, 333, ...

**Question 13**

10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?

10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?

A. 3

B. 5

C. 7

D. Cannot be determined

Ans. C

Explanation:

1 woman's 1 day's work=1/70 1 child's 1 day's work =1/140 (5 women + 10 children)'s day's work =5/70 +10/140=1/14 +1/14=1/7 5 women and 10 children will complete the work in 7 days.

**Question 14**

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?

A. Rs. 375

B. Rs. 400

C. Rs. 600

D. Rs. 800

Ans. B

Explanation:

C's 1 day's work = 1/3 - [1/6 + 1/8]= 1/3 - 7/24= 1/24 A's wages : B's wages : C's wages = 1/6: 1/8: 1/24= 4 : 3 : 1. C's share (for 3 days) = Rs.[3 x 1/24 x 3200] = Rs. 400.

Question 15

The product of two numbers is 9375 and the quotient, when the larger one is divided by the smaller, is 15. The sum of the numbers is:

A. 380

B. 395

C. 400

D. 425

Ans. C

Explanation:

Let the numbers be x and y. Then, xy = 9375 and x/y=15 Xy/(x/y)=9375/15 y2 = 625. y = 25. x = 15y = (15 x 25) = 375. Sum of the numbers = x + y = 375 + 25 = 400.

**Question 16**

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A. 25% increase

B. 50% increase

C. 50% decrease

D. 75% decrease

Ans. B

Explanation:

Let original length = x and original breadth = y. Original area = xy. New length =x/2 New breadth = 3y. New area=[(x/2)*3y]=(3/2)xy Increase % =[(1/2)xy*(1/xy)*100]%=50%

**Question 17**

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

A. 1520 m2

B. 2420 m2

C. 2480 m2

D. 2520 m2

Ans. D

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103. Solving the two equations, we get: l = 63 and b = 40. Area = (l x b) = (63 x 40) m2 = 2520 m2.

**Question 18**

In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years age which is 48. What is the total number of students in the school?

In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years age which is 48. What is the total number of students in the school?

A. 72

B. 80

C. 120

D. 100

Ans. D

**Question 19**

Point out the error in the program?

#include

int main()

{

struct emp

{

char name[20];

float sal;

};

struct emp e[10];

int i;

for(i=0; i<=9; i++)

scanf("%s %f", e[i].name, &e[i].sal);

return 0;

}

Point out the error in the program?

#include

int main()

{

struct emp

{

char name[20];

float sal;

};

struct emp e[10];

int i;

for(i=0; i<=9; i++)

scanf("%s %f", e[i].name, &e[i].sal);

return 0;

}

A. Error: invalid structure member

B. Error: Floating point formats not linked

C. No error

D. None of above

Ans. B

Explanation:

At run time it will show an error then program will be terminated. Sample output: Turbo C (Windwos) Sample 12.123 scanf : floating point formats not linked Abnormal program termination

**Question 20**

Point out the error in the program?

#include

int main()

{

struct emp

{

char name[20];

float sal;

};

struct emp e[10];

int i;

for(i=0; i<=9; i++)

scanf("%s %f", e[i].name, &e[i].sal);

return 0;

}

Point out the error in the program?

#include

int main()

{

struct emp

{

char name[20];

float sal;

};

struct emp e[10];

int i;

for(i=0; i<=9; i++)

scanf("%s %f", e[i].name, &e[i].sal);

return 0;

}

A. Error: invalid structure member

B. Error: Floating point formats not linked

C. No error

D. None of above

Ans. B

Explanation:

At run time it will show an error then program will be terminated. Sample output: Turbo C (Windwos) c:\>myprogram Sample 12.123 scanf : floating point formats not linked Abnormal program termination

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**Question 21**

What will be the output of the program ?

#include

int main()

{

char p[] = "%d\n";

p[1] = 'c';

printf(p, 65);

return 0;

}

What will be the output of the program ?

#include

int main()

{

char p[] = "%d\n";

p[1] = 'c';

printf(p, 65);

return 0;

}

A. A

B. a

C. c

D. 65

Ans. A

Explanation:

Step 1: char p[] = "%d\n"; The variable p is declared as an array of characters and initialized with string "%d" Step 2: p[1] = 'c'; Here, we overwrite the second element of array p by 'c'. So array p becomes "%c". Step 3: printf(p, 65); becomes printf("%c", 65); Therefore it prints the ASCII value of 65. The output is 'A'.

**Question 22**

What will be the output of the program ?

#include

#include

int main()

{

char str1[20] = "Hello", str2[20] = " World";

printf("%s\n", strcpy(str2, strcat(str1, str2)));

return 0;

}

What will be the output of the program ?

#include

#include

int main()

{

char str1[20] = "Hello", str2[20] = " World";

printf("%s\n", strcpy(str2, strcat(str1, str2)));

return 0;

}

A. Hello

B. World

C. Hello World

D. WorldHello

Ans. C

Explanation:

Step 1: char str1[20] = "Hello", str2[20] = " World"; The variable str1and str2 is declared as an array of characters and initialized with value "Hello" and " World" respectively. Step 2: printf("%s\n", strcpy(str2, strcat(str1, str2))); => strcat(str1, str2)) it append the string str2 to str1. The result will be stored in str1. Therefore str1 contains "Hello World". => strcpy(str2, "Hello World") it copies the "Hello World" to the variablestr2. Hence it prints "Hello World".

**Question 23**

Point out the error in the program

#include

int main()

{

int i;

#if A

printf("Enter any number:");

scanf("%d", &i);

#elif B

printf("The number is odd");

return 0;

}

Point out the error in the program

#include

int main()

{

int i;

#if A

printf("Enter any number:");

scanf("%d", &i);

#elif B

printf("The number is odd");

return 0;

}

A. Error: unexpected end of file because there is no matching #endif

B. The number is odd

C. Garbage values

D. None of above

Ans. A

Explanation:

The conditional macro #if must have an #endif. In this program there is no#endif statement written.

**Question 24**

Point out the error in the program

#include

#define SI(p, n, r) float si; si=p*n*r/100;

int main()

{

float p=2500, r=3.5;

int n=3;

SI(p, n, r);

SI(1500, 2, 2.5);

return 0;

}

Point out the error in the program

#include

#define SI(p, n, r) float si; si=p*n*r/100;

int main()

{

float p=2500, r=3.5;

int n=3;

SI(p, n, r);

SI(1500, 2, 2.5);

return 0;

}

A. 26250.00 7500.00

B. Nothing will print

C. Error: Multiple declaration of si

D. Garbage values

Ans. C

Explanation:

The macro #define SI(p, n, r) float si; si=p*n*r/100; contains the error. To remove this error, we have to modify this macro to #define SI(p,n,r) p*n*r/100

**Question 25**

What will be the output of the program?

#include

int main()

{

float d=2.25;

printf("%e,", d);

printf("%f,", d);

printf("%g,", d);

printf("%lf", d);

return 0;

}

What will be the output of the program?

#include

int main()

{

float d=2.25;

printf("%e,", d);

printf("%f,", d);

printf("%g,", d);

printf("%lf", d);

return 0;

}

A. 2.2, 2.50, 2.50, 2.5

B. 2.2e, 2.25f, 2.00, 2.25

C. 2.250000e+000, 2.250000, 2.25, 2.250000

D. error

Ans. C

Explanation:

printf("%e,", d); Here '%e' specifies the "Scientific Notation" format. So, it prints the 2.25 as 2.250000e+000. printf("%f,", d); Here '%f' specifies the "Decimal Floating Point" format. So, it prints the 2.25 as 2.250000. printf("%g,", d); Here '%g' "Use the shorter of %e or %f". So, it prints the 2.25 as 2.25. printf("%lf,", d); Here '%lf' specifies the "Long Double" format. So, it prints the 2.25 as 2.250000.

**Question 26**

What will be the output of the program?

#include

#include

int main()

{

float n=1.54;

printf("%f, %f\n", ceil(n), floor(n));

return 0;

}

What will be the output of the program?

#include

#include

int main()

{

float n=1.54;

printf("%f, %f\n", ceil(n), floor(n));

return 0;

}

A. 2.000000, 1.000000

B. 1.500000, 1.500000

C. 1.550000, 2.000000

D. 1.000000, 2.000000

Ans. A

Explanation:

ceil(x) round up the given value. It finds the smallest integer not < x. floor(x) round down the given value. It finds the smallest integer not > x. printf("%f, %f\n", ceil(n), floor(n)); In this line ceil(1.54) round up the 1.54 to 2 and floor(1.54) round down the 1.54 to 1. In the printf("%f, %f\n", ceil(n), floor(n)); statement, the format specifier "%f %f" tells output to be float value. Hence it prints 2.000000 and 1.000000.

**Question 27**

What will be the output of the program?

#include

int main()

{

float a=0.7;

if(a < 0.7f)

printf("C\n");

else

printf("C++\n");

return 0;

}

What will be the output of the program?

#include

int main()

{

float a=0.7;

if(a < 0.7f)

printf("C\n");

else

printf("C++\n");

return 0;

}

A. C

B. C++

C. Compiler error

D. Non of above

Ans. B

Explanation:

if(a < 0.7f) here a is a float variable and 0.7f is a float constant. The float variable a is not less than 0.7f float constant. But both are equal. Hence the ifcondition is failed and it goes to else it prints 'C++'

**Question 28**

What will be the output of the program?

#include

int main()

{

float f=43.20;

printf("%e, ", f);

printf("%f, ", f);

printf("%g", f);

return 0;

}

What will be the output of the program?

#include

int main()

{

float f=43.20;

printf("%e, ", f);

printf("%f, ", f);

printf("%g", f);

return 0;

}

A. 4.320000e+01, 43.200001, 43.2

B. 4.3, 43.22, 43.21

C. 4.3e, 43.20f, 43.00

D. Error

Ans. A

Explanation:

printf("%e, ", f); Here '%e' specifies the "Scientific Notation" format. So, it prints the 43.20 as 4.320000e+01. printf("%f, ", f); Here '%f' specifies the "Decimal Floating Point" format. So, it prints the 43.20 as 43.200001. printf("%g, ", f); Here '%g' "Use the shorter of %e or %f". So, it prints the 43.20 as 43.2.

**Question 29**

If the size of an integer is 4 bytes, What will be the output of the program ?

#include

#include

int main()

{

printf("%d\n", strlen("123456"));

return 0;

}

If the size of an integer is 4 bytes, What will be the output of the program ?

#include

#include

int main()

{

printf("%d\n", strlen("123456"));

return 0;

}

A. 6

B. 12

C. 7

D. 2

Ans. A

Explanation:

The function strlen returns the number of characters int the given string. Therefore, strlen("123456") contains 6 characters. The output of the program is "6".

**Question 30**

What will be the output of the program ?

#include

int main()

{

int arr[5], i=0;

while(i<5)

arr[i]=++i;

for(i=0; i<5; i++)

printf("%d, ", arr[i]);

return 0;

}

What will be the output of the program ?

#include

int main()

{

int arr[5], i=0;

while(i<5)

arr[i]=++i;

for(i=0; i<5; i++)

printf("%d, ", arr[i]);

return 0;

}

A. 1, 2, 3, 4, 5,

B. Garbage value, 1, 2, 3, 4,

C. 0, 1, 2, 3, 4,

D. 2, 3, 4, 5, 6,

Ans. B

Explanation:

Since C is a compiler dependent language, it may give different outputs at different platforms. We have given the TurboC Compiler (Windows) output. Please try the above programs in Windows (Turbo-C Compiler) and Linux (GCC Compiler), you will understand the difference better.

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__Essar Placement Paper Syllabus:__

####
__Quantitative Aptitude Syllabus:__

- Probability
- Permutations & Combinations
- Algebra
- Averages
- Time Speed & Distance
- Time & Work
- Profit & Loss
- Ratio & Proportion
- Simple & Compound Interest
- Percentage
- Number Series
- Mixtures & Alligations
- Simplification
- Number System
- Heights and Distances
- Geometry & Mensuration
- Data Sufficiency
- Logarithms
- Progressions
- LCM and HCL
- Pipes and Cisterns
- Partnership
- Boats and Streams
- Areas, Volumes

####
__Reasoning Syllabus:__

- Number Series
- Letter Series
- Anologies
- Puzzles
- Syllogisms
- Binary Logic
- Clocks & Calendars
- Cubes & Dice
- Classification
- Blood Relations
- Coding-Decoding
- Data Sufficiency
- Seating Arrangement
- Venn Diagrams
- Problem Solving
- Coded Inequalities
- Double Lineup
- Logical Deductions
- Routes & Networks
- Grouping & Selections
- Evaluating Course of Action
- Statements and Conclusions
- Mathematical and Computer Operations
- Critical Reasoning
- Inferences
- Situation Reaction Test
- Decision Making
- Symbols and Notations
- Direction Sense Test
- Logical Sequence Of Words
- Assertion and Reason
- Verification of Truth of the Statement
- Statements and Assumptions
- Data Interpretation

####
__Verbal Ability Syllabus:__

- Synonyms
- Antonyms
- Sentence Completion
- Spelling Test
- Passage Completion
- Sentence Arrangement
- Idioms and Phrases
- Para Completion
- Error Correction (Underlined Part)
- Fill in the blanks
- Synonyms
- Prepositions
- Active and Passive Voice
- Spotting Errors
- Substitution
- Transformation
- Sentence Improvement
- Joining Sentences
- Error Correction (Phrase in Bold)
- Articles
- Gerunds
- Identify the Errors
- Plural Forms
- Odd Words
- Prepositions
- Suffix
- Tense
- Adjectives
- Homophones
- Identify the Sentences
- Nouns
- Prefix
- Sentence Pattern
- Tag Questions

Dear readers, the syllabus and

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