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**Placement papers of Ashok Leyland 2016-2015**. Learn and practice the placement papers and interview questions answers of Ashok Leyland and find out how much you score before you appear for your next interview and written test.

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__Ashok Leyland Placement Papers 2016 & Interview Questions:__

**1. In triangle ABC, angle B is a right angle. If AC is 6cm, and D is the mid-point of side AC, the length of BD is**

A.4cm B.6cm C.3cm D.3.5cm

Answer: C

Explanation:

In a right angled triangle, the median is half the length of the hypotenuse = ½(6) = 3 cm.

**2. Average cost of 5 apples and 4 mangoes is Rs. 36. The average cost of 7 apples and 8 mangoes is Rs. 48. Find the total cost of 24 apples and 24 mangoes ?**

A.1044 B.2088 C.720 D.324

Answer: B

Explanation:

Average cost of 5 apples and 4 mangoes = Rs. 36 Total cost = 36 * 9 = 324 Average cost of 7 apples and 8 mangoes = 48

Total cost = 48 * 15 = 720 Total cost of 12 apples and 12 mangoes = 324 + 720 = 1044 Therefore,

cost of 24 apples and 24 mangoes = 1044 * 2 = 2088

**3. The average weight of 8 person's increases by 2.5 kg. When a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ?**

A.76 kg B.76.5 kg C.85 kg D.None of these

Answer: C

Explanation:

Total weight increased = (8 x 2.5) kg = 20 kg. Weight of new person = (65 + 20) kg = 85 kg.

**4. How many numbers between 1to 1000(both excluded) are both squares and cubes ?**

A.3 B.1 C.2 D.none

Answer: B

Explanation:

Try with whole cubes as they are fewer in number. 4^3 = 64 and 8^2 = 64 i.e. 64 only

**5. I bought 5 pens, 7 pencils and 4 erasers. Rajan bought 6 pens, 8 erasers and 14 pencils for an amount which was half more than what I had paid. What percent of the total amount paid by me was paid for the pens ?**

A.37.5% B.62.5% C.50% D.None of these

Answer: B

Explanation:

Let one pen, one pencil and one eraser cost n, p and r units respectively. Let the amount paid by me be A units. I pay (5n + 7p + 4r) = A ........

Eqn. (1) While Rajan pays (6n + 14p + 8r) = 1.5 A ............ Eqn. (2). Multiply equation (1) by 2. We Get (10n + 14p + 8r) = 2A ........ Eqn. (3).

Comparing equations (2) and (3), we see that while Rajan gets 4 pens less, he pays 0.5A units less. Thus, A = the price of 8 pens.

Therefore the % of the total price paid by me initially, which was used for pens is (5/8) (100) = 62.5%.

**6. Two people agree to meet on January 9, 2005 between 6.00 P.M. to 7.00 P.M., with the understanding that each will wait no longer than 20 minutes**

**for the other. What is the probability that they will meet ?**

A.5/9 B.7/9 C.2/9 D.4/9

Answer: D

Explanation:

They can meet when A comes between 6: 00 = 6: 40. And so B can join him between 6: 20 = 7: 00. Similarly, the process can be reversed.

Therefore p=(40 / 60)2 = 4/9.

**7. Find the series ? 42 40 38 35 33 31 28 ___ ___**

A.25 22 B.26 23 C.26 24 D.25 23

Answer: C

Explanation:

This is an alternating subtraction series in which 2 is subtracted twice, then 3 is subtracted once, then 2 is subtracted twice, and so on.

**8. Steel Express runs between Tatanagar and Howrah and has five stoppages in between. Find the number of different kinds of one-way second class**

**ticket that Indian Railways will have to print to service all types of passengers who might travel by Steel Express ?**

A.49 B.42 C.21 D.7

Answer: B

Explanation:

We have 5 stations + (T + H) = 7 stations. Out of the 7 stations, we have to print tickets connecting any 2; i.e. arrangements of 7 things,

any 2 at a time, i.e. No. of tickets = 7P2 = 42.

**9. The horizontal distance of a kite from the boy flying it is 30 m and 50 m of cord is out from the roll. If the wind moves the kite horizontally at**

**the rate of 5 km per hour directly away from the boy, how fast is the cord being released ?**

A.3 km per hour B.4 km per hour C.5 km per hour D.6 km per hour

Answer: D

**10. Two players A and B play the following game. A selects an integer from 1 to 10, inclusive of both. B then adds any positive integer from 1 to 10,**

**both inclusive, to the number selected by A. The player who reaches 46 first wins the game. If the game is played properly, A may win the game if:**

A.A selects 8 to begin with B.A selects 2 to begin with C.A selects any number greater than 5 D.None of the above

Answer:D

Explanation:

Since repetition of numbers is allowed, both are equally free to win the game.

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**11. A watch dealer incurs an expense of Rs 150 for producing every watch. He also incurs an additional expenditure of Rs. 30,000; this is independent**

**of the number of watches produced. If he is able to sell a watch during the season, he sells it for Rs. 250. If he fails to do so, he has to sell each**

**watch for Rs. 100. If he is able to sell only 1200 out of the 1500 watches he has made in the season, then in the season he has made a profit of:**

A.Rs. 90,000 B.Rs. 75,000 C.Rs. 45,000 D.Rs 60,000

Answer: C

Explanation:

One each of the 1200 watches that he sells in the season, he makes a profit of Rs. 100(i.e. Rs. 250 - Rs. 150).

On each of the 300 (i.e. 1500 - 1200) watches that are not sold, he incurs a loss of Rs. 150, which is the manufacturing cost.

His additional expense is Rs. 30,000 (given). Thus his net profit in the season is Rs. (1, 20,000 - 45,000 - 30,000) = Rs.45,000.

**12. Find the next term in series:- 5, 10, 13, 26, 29, 58, 61, ____.**

A.64 B.122 C.12 D.128

Answer: B

Explanation:

Multiplied by 2 & increased by 3. 5 * 2= 10, 10 + 3 = 13, 13 * 2 = 26, 26 + 3 = 29, 29 * 2 = 58, 58 + 3 = 61, So missing number is 61 * 2 = 122.

**13. Distance between A and B is 72 km. Two men started walking from A and B at the same time towards each other. The person who started from A travelled uniformly with average speed 4 kmph. While the other man travelled with varying speeds as follows: In first hour his speed was 2 kmph, in the second hour it was 2.5 kmph, in the third hour it was 3 kmph, and so on. When will they meet each other ?**

A.7 hours B.10 hours C.35 km from A D.midway between A & B

Answer: B & D

Explanation:

The Let x and y be the persons who started from A and B respectively. Midway between A and B means 36 km. From A and B both. X will take 9 hours

to reach the midpoint. In 9 Hours y will also cover 2 + 2.5 + 3 + 3.5 + 4 + 4.5 + 5 + 5.5 + 6 = 36 km. Thus y will also reach the midpoint at the same time.

**14. The sum of ages of 5 children born at the interval of 3 years each is 50 years. What is The age of youngest child ?**

A.4 years B.8 years C.10 years D.none of these

Answer:

Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years. Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 X = 4

**15. DIRECTIONS for Questions 15 and 16: Answer the questions on the basis of the information given below. New Age Consultants have three consultants Gyani, Medha and Buddhi. The sum of the number of projects handled by Gyani and Buddhi individually is equal to the number of projects in which Medha is involved. All three consultants are involved together in 6 projects. Gyani works with Medha in 14 projects. Buddhi has 2 projects with Medha but without Gyani, and 3 projects with Gyani but without Medha. The total number of projects for New Age Consultants is one less than twice the number of projects in which more than one consultant is involved.**

**What is the number of projects in which Medha alone is involved ?**

A.Uniquely equal to zero B.Uniquely equal to 1

C.Uniquely equal to 4 D.Cannot be determined uniquely

Answer: B

Explanation:

As per the given data we get the following: G + B = M + 16 Also, M + B + G + 19 = (2 x 19) - 1 i.e. (G + B) = 18 - M Thus, M + 16 = 18 - M i.e. M = 1

**16. What is the number of projects in which Gyani alone is involved ?**

A.Uniquely equal to zero B.Uniquely equal to 1

C.Uniquely equal to 4 D.Cannot be determined uniquely

Answer: D

Explanation:

Putting the value of M in either equation, we get G + B = 17. Hence neither of two can be uniquely determined.

**17. DIRECTIONS for Questions 17 and 18: Answer the questions on the basis of the information given below. Five horses, Red, White, Grey, Black and Spotted participated in a race. As per the rules of the race, the persons betting on the winning horse get four times the bet amount and those betting on the horse that came in second get thrice the bet amount. Moreover, the bet amount is returned to those betting on the horse that came in third, and the rest lose the bet amount. Raju bets Rs. 3000, Rs. 2000 Rs. 1000 on Red, White and Black horses respectively and ends up with no profit and no loss.**

**Which of the following cannot be true ?**

A.At least two horses finished before Spotted.

B.Red finished last.

C.There were three horses between Black and Spotted.

D.There were three horses between White and Red.

Answer: D

Explanation:

There cannot be three horses between White and Red --- as for that to happen one of them should be in the first position and the other in the last position. Hence option 4 is correct ---as it is not possible.

**18. Suppose, in addition, it is known that Grey came in fourth. Then which of the following cannot be true ?**

A.Spotted came in first. B.Red finished last.

C.White came in second. D.Black came in second

Answer: C

Explanation:

If Grey came fourth, then it must be one of the first two possibilities. In both these cases, white cannot come second. Hence, option 3 is correct.

**19. DIRECTIONS for Questions 30 and 32: Answer the questions on the basis of the information given below.**

**1. There are three houses on each side of the road. 2. These six houses are labeled as P, Q, R, S, T and U.**

**3. The houses are of different colors, namely, Red, Blue, Green, Orange, Yellow and white. 4. The houses are of different heights.**

**5. T, the tallest house, is exactly opposite to the Red coloured house. 6. The shortest house is exactly opposite to the Green coloured house.**

**7. U, the Orange coloured house, is located between P and S. 8. R, the Yellow coloured house, is exactly opposite to P. 9. Q, the Green coloured house, is exactly opposite to U. 10. P, the White coloured house, is taller than R, but shorter than S and Q. What is the colour of the tallest house ?**

A.Red B.Blue C.Green D.Yellow

Answer: B

Explanation:

The tallest house is T and its colour is blue.

**20. What is the colour of the house diagonally opposite to the Yellow coloured house ?**

A.White B.Blue C.Green D.red

Answer: D

Explanation:

The house diagonally opposite to the Yellow coloured house is S which has red colour. Hence, option D

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**21. Which is the second tallest house ?**

A.P B.S C.Q D.cannot be determined

Answer: D

Explanation:

The second tallest house can be either S or Q. Hence, option D.

**22. DIRECTIONS for Questions 22 and 25: Answer the questions on the basis of the information given below. In a sports event, six teams (A, B, C, D, E and F) are competing against each other. Matches are scheduled in two stages. Each team plays three matches in Stage-I and two matches in Stage-II.**

**No team plays against the same team more than once in the event. No ties are permitted in any of the matches. The observations after the completion of**

**Stage-I and Stage-II are as given below. Stage-I: One team won all the three matches. Two teams lost all the matches. D lost to A but won against C and F. E lost to B but won against C and F.B lost at least one match. F did not play against the top team of Stage-I. Stage-II: The leader of Stage-I lost the next two matches. Of the two teams at the bottom after Stage-I, one team won both matches, while the other lost both matches. One more team lost both matches in Stage-II.**

**The team(s) with the most wins in the event is (are):**

A.A B.A & C C.F D.B & E

Answer: D

Explanation:

Stage I can be represented as: D -- A B -- A D - C A -- C D -- F F -- B E -- B E -- C E - F since no team plays against the same team more than once

in the event Stage II can be represented as: A -- E A -- F F -- C B -- C D -- B D - E Now, we can calculate the number of times each team has won.

Team Stage I Stage II Total A 3 0 3 B 2 2 4 C 0 0 0 D 2 0 2 E 2 2 4 F 0 2 2 It can be observed from the above table that B and E have most wins in the event.

Hence, option D

**23. The two teams that defeated the leader of Stage-I are:**

A.F & D B.E & F C.B & D D.E & D

Answer: B

Explanation:

E and F defeated A. Hence, option B.

**24. The only team(s) that won both the matches in Stage-II is (are):**

A.B B.E & F C.A, E & F D.B, E & F

Answer: D

Explanation:

B, E and F are the three teams that won both matches in stage II. Hence, option D.

**25. The teams that won exactly two matches in the event are:**

A.A, D & F B.D & E C.E & F D.D, E & F E.D & F

Answer: E

Explanation:

From the table it is clear that the team that won exactly two matches in the event is D and F. Hence, option E.

**26. DIRECTIONS for Questions 26 and 28: Answer the questions on the basis of the information given below. A visits Vizag where his brother P resides. P stays with his father Q and mother S. P's grandfather, R also stays with him. P has two children B and C. B's husband is X. C is married to Y,**

**who is a wrestler. C's son T welcomed A on his visit. How is related to B ?**

A.Niece B.Nephew C.Cousin D.son

Answer: B

**27. How is S related to C ?**

A.Mother B.Grandmother C.Aunt D.Cannot be determined

Answer: B

**28. How is P related to X ?**

A.Mother-in-law B.Mother C.Father-in-law D.Cannot be determined

Answer: C

**29. DIRECTIONS for Questions 29 and 31: Answer the questions on the basis of the information given below. "In a class of 70 students, 30 failed in mathematics and 35 failed in Statistics. Ten students passed in both the subjects." How many failed in both the subject ?**

A.65 B.60 C.5 D.15

Answer: C

**30. How many students passed only in Mathematics ?**

A.40 B.30 C.15 D.20

Answer: B

**31. How many students passed in exactly one of the two subjects ?**

A.60 B.55 C.40 D.35

Answer: B