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**Placement papers of Apps Associates 2016-2015**. Learn and practice the placement papers and interview questions answers of Apps Associates and find out how much you score before you appear for your next interview and written test.

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__Apps Associates Placement Papers 2016 & Interview Questions:__

__Apps Associates Placement Papers 2016 & Interview Questions:__

**1. Find the next term in series? 25 16 9 4 1 0**

A.-1 B.1 C.0 D.none

Answer: B

Explanation:

5 ^ 2, 4 ^ 2, 3 ^ 2, 2 ^ 2, 1^ 2, 0 ^ 2, (-1) ^2 = 1

**2. 123456147, 12345614, 2345614, 234561, (.....)**

A.3456 B.2345 C.23456 D.34561

Answer: D

Explanation:

The digits are removed one by one from the end as well as from the beginning in order so as to obtain the next term of the series.

**3. 45 grinders brought at Rs. 2215/-.transpot expense Rs 2190/-.2760/- on octroi. Find selling price/piece to make profit of 20%?**

A.2585 B.2225 C.2790 D.3325

Answer: C

Explanation:

Grider price\piece = 2215 Transport exp\piece= (2190+2760)/45 = 110 Total acquiring price of grinder\piece = 2215+110 = 2325

20% profit on C = (2325 * 20)/100 = 465 Selling price C+D = 2790

**4. The last digit of (2004) ^5 is**

A.4 B.8 C.6 D.2

Answer: A

Explanation:

As 2004 = 2000 + 4, the last digits of (2004) ^5 and 4^5 are equal. i.e. 4^5 = 1024 so unit digit is 4.

**5. In a 2 digit number unit's place is halved and ten's place is doubled. Difference between the numbers is 37.Digit in unit's place is 2 more than ten's place.**

**Find the number?**

A.24 B.46 C.42 D.NONE

Answer: B

Explanation:

Let the ten's digit be x then unit digit= x+2 Number = 10x+(x+2) = 11x+2 -------- (1) The number obtained by doubling digit in ten's place

& by reducing unit's place digit to half the original value = 2(10x) + (x+2)/2 -------- (2) Difference between the numbers (1) - (2) = 37.

By solving equation X= 4 Therefore number 11* 4 + 2= 46.

**6. If x - y + z = 19, y + z =20, x - z = 3, find the value of x + 4y - 5z ?**

A.22 B.38 C.17 D.none

Answer: D

Explanation:

X - y + z = 19.......Eqn 1 y + z = 20............Eqn 2 x - z = 3...............Eqn 3 Adding Eqn 1 and Eqn 2 gives

x - y + z + y + z = x + 2z = 19 + 20 = 39 Subtracting Eqn 3 from the above gives x + 2z -(x - z) = 3z = 39 - 3 = 36............z = 12 From Eqn 2,

y + 12 = 20 ......................y = 8 From Eqn 1, x - 8 + 12 = x + 4 = 19....x = 15 Then, x + 4y - 5z = 15 + (4x8) - (5x12) = 15 + 32 - 60 = -13

**7. A is 4 yrs old and B is thrice A. when A is 12 yrs, how old will B be ?**

A.16 B.20 C.24 D.28

Answer: B

Explanation:

A= 4 years B = 3times A= 12 years A will be 12 after 8 years when A will be 12 years B will be 12 + 8 = 20 years

**8. A motorboat whose speed is 15 kmph in still water goes 30 kmph downstream and comes back in a total of 4hrs 30min.Find the speed of the stream in kmph ?**

A.4 B.5 C.24 D.10

Answer: B

Explanation:

Let the speed of the stream be x km/hr. Then, Speed downstream = (15 + x) km/hr, Speed upstream = (15 - x) km/hr.

Therefore 30 / (15 + x) + 30 / (15 - x) = 4(1/2) 900/ (225 - x^ 2) = 9/2 9x2 = 225 x2 = 25 x = 5 km/hr.

**9. A garrison had provision for a certain number of days. After 10 days, 1/5 of the men desert and it is found that the provisions will now last just as long as**

**before. How long was that ?**

A.15 B.25 C.35 D.50

Answer: D

Explanation:

Let initially there be X men having food for Y days. After 10 days X men had food for Y-10 days. Also X - X/5 = 4/5X had food for Y days.

Apply chain rule X(Y-10) = (4/5) X *Y (X*Y) - 10 X=[4(X*Y)/5] 5(X*Y) - 4(X*Y)=50X X*Y = 50XY = 50

**10. Find the equation whose roots are 9 and 5 ?**

A.x2 + 14x + 45 = 0 B.x2 + 14x + 49 = 0 C.x2 + 10x + 45 = 0

D.NONE

Answer: A

Explanation:

Finding the roots of given equations x2 - 14x + 45 = 0 x2 - 9 x - 5 x + 45 = 0 (x - 5) (x - 9) = 0

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**11. Find the next term in series - Y W U S Q O M ?**

A.P B.J C.L D.NONE

Answer: D

Explanation:

Correct ans should be K.

**12. In a triangle ABC, the lengths of the sides AB and AC equal 17.5 cm and 9 cm respectively. Let D be a point on the line segment BC such that AD**

**is perpendicular to BC. If AD = 3 cm, then what is the radius (in cm) of the circle circumscribing the triangle ABC?**

A.17.05 B.27.85 C.22.45 D.26.25

Answer: D

**13. Train A starts from Meerut at 12:00 pm & reach at Delhi on 2:30 pm & train B starts from Delhi at 12:15pm and reach at Meerut on 2:15pm. So, when both trains crosses each other ?**

A.1.00PM B.1.15PM C.1.30PM D.NONE

Answer: B

Explanation:

Let the distance between Meerut & Delhi be x kms & let trains meet y hours after 12.15pm Speed of A= x/150 kms/min.

speed of B = x/120 kms / min. Distance covered by A in (y+15) min+distance covered by B in y hours=x (x/150)* (y+15) + (x/120) * y = x Equating

the equations Y=60 Hence trains meet at 1.15 pm.

**14. In election a candidate who gets 42% of votes, is lost by 112 votes. What is the total number of votes polled?**

A.650 B.680 C.710 D.700

Answer: D

Explanation:

Let the total number of votes polled be x, then votes polled by other candidate = (100-42)% of x = 58% of x Therefore 58% of x- 42% of x = 112 X= 700.

**15. A boat covers 2 kms distance downstream in 1/2 hour. while it comes back in 1 hour. Then the velocity of the current is**

A.1 km/hr B.2 km/hr C.1.15 km/hr D.3 km/hr

Answer: A

Explanation:

Rate down stream = (2/0.5) kmph Rate upstream = (2/1) kmph Therefore velocity of current = ½ (4-2) = 1kmph.

**16. A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was:**

A.2000 B.10000 C.15000 D.20000

Answer: C

Explanation:

Principal = Rs. (100 x 5400) / (12 x 3)= Rs. 15000.

**17. A man traveled a certain distance at the rate of 15 miles/hour and came back at the rate of 10 miles/hour. What is his average speed ?**

A.10 miles/hour B.15 miles/hour C.17 miles/hour D.12 miles/hour

Answer : D

Explanation:

Average speed = (2* 15* 10) / 25 = 300/25 12 miles/ hour.

**18. The addition of 2 number difference of 2 number is a perfect square & the difference of both perfect square also a perfect square. Then find out this number ?**

A.2,4 B.4,4 C.6,9 D.6,2

Answer: D

Explanation:

By checking the given options =>6, 2 =>6 + 2 = 8, 6 - 2 = 4 and 8 - 4 = 4

**19. The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression.**

**Then which element of the series should necessarily be equal to zero ?**

A.1st B.9th C.12th D.NONE

Answer: C

Explanation:

lets the first term of ap is a and difference is d then third term will be =a+2d 15th will be=a+14d 6th will be =a+5d 11th will be =a+10d 13th will be=a+12d then

the equation will be as a+2d+a+14d = a+5d+a+10d+a+12d 2a+16d = 3a+27d a+11d=0 simply we can understand a+11d will be the 12th term of arithmetic progression so the correct answer is 12

**20. X + Y = 6, then XY = ?**

A.36 B.8 C.3 D.30

Answer: B

Explanation:

Lets us consider x = 4, y = 2 x + y = 4 + 2 = 6 xy = 4*2 = 8

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**21. There are three coins of Re1, 50 ps, 25 ps having ratio of 13:11:3. The total sums of money are 77, and then find out how much Re. 1 coin is there ?**

A.22 B.52 C.27 D.NONE

Answer: B

Explanation:

Let number if coins of each denomination be x. Then as they are in ratio of 13:11:3 Then (13/27)x + (11/27)(1/2)x + (3/27)(1/4)x = 77 Taking L.C.M.

& equating LHS & RHS gives x = 108 Number of 1 rupee coins = (13/27)*108 = 52.

**22. Ten years ago, the ages of the members of a joint family of eight people added up to 231 years. Three years later, one member died at the age of 60 years**

**and a child was born during the same year. After another three years, one more member died, again at 60, and a child was born during the same year.**

**The current average age of this eight member joint family is nearest to:**

A.23years B.22years C.21years D.24years

Answer: D

Explanation:

The sum of the ages of the members of the family ten years ago = 231. The sum of the ages of the members of the family seven years ago = 231 + (3 × 8) - 60 =195.

The sum of the ages of the members of the family four years ago = 195 + (3 × 8) - 60 = 159 ∴ The sum of the ages of the members of the family

now = 159 + (4 × 8) = 191 ∴ Required average = 191/8 = 23.875 ≈ 24.

**23. A test has 50 questions. A student scores 1 mark for a correct answer, -1/3 for a wrong answer, and -1/6 for not attempting a question.**

**If the net score of a student is 32, the number of questions answered wrongly by that student cannot be less than ?**

A.3 B.6 C.12 D.9

Answer: A

Explanation:

Let the number of correct answers be 'x', number of wrong answers be 'y' and number of questions not attempted be 'z'.

Thus, x + y + z = 50 ... (i) And x - y/3 - z/6 = 32 The second equation can be written as, 6x - 2y - z = 192 ... (ii) Adding the two equations we get,

7x - y = 242 or x = (242 + y)/7 Since, x and y are both integers, y cannot be 1 or 2. The minimum value that y can have is 3.

**24. How many even integers n, where 100**

A.40 B.37 C.38 D.39

Answer: D

Explanation:

There are 101 integers in all, of which 51 are even. From 100 to 200, there are 14 multiples of 7, of which 7 are even.

There are 11 multiples of 9, of which 6 are even. But there is one integer (i.e. 126) that is a multiple of both 7 and 9 and also even.

Hence the answer is (51 - 7 - 6 + 1) = 39

**25. DIRECTIONS for Questions 25 and 26: Answer the questions on the basis of the information given below. The Head of a newly formed government**

**desires to appoint five of the six elected members A, B, C, D, E and F to portfolios of Home, Power, Defense, Telecom and Finance.**

**F does not want any portfolio if D gets one of the five. C wants either Home or Finance or no portfolio. B says that if D gets either Power or**

**Telecom then she must get the other one. E insists on a portfolio if A gets one. Which is a valid assignment ?**

A.A-Home, B-Power, C-Defense, D-Telecom, E-Finance.

B.C-Home, D-Power, A-Defense, B-Telecom, E-Finance

C.A-Home, B-Power, E-Defense, D-Telecom, F-Finance.

D.B-Home, F-Power, E-Defense, C-Telecom, A -Finance

Answer: B

Explanation:

From the above information we can note that => If D gets any then F does not want any .So, option C invalid. => C wants in either

**26. If A gets Home and C gets Finance, then which is NOT a valid assignment for Defense and Telecom ?**

A.D-Defense, B-Telecom. B.F-Defense, B-Telecom

C.B-Defense, E-Telecom. D.B-Defense, D-Telecom.

Answer: D

Explanation:

As B says that if D gets either Power or Telecom then she must get the other one option D is invalid.

in Home or Finance. Therefore option A and D invalid => So, option B answer.

**27. DIRECTIONS for Questions 27 to 28: Answer the questions on the basis of the information given below. Rang Barsey Paint Company (RBPC) is in the**

**business of manufacturing paints. RBPC buys RED, YELLOW, WHITE, ORANGE, and PINK paints. ORANGE paint can be also produced by mixing RED and**

**YELLOW paints in equal proportions. Similarly, PINK paint can also be produced by mixing equal amounts of RED and WHITE paints. Among other paints,**

**RBPC sells CREAM paint, (formed by mixing WHITE and YELLOW in the ratio 70:30) AVOCADO paint (formed by mixing equal amounts of ORANGE and**

**PINK paint) and WASHEDORANGE paint (formed by mixing equal amounts of ORANGE and WHITE paint). The following table provides the price at which**

**RBPC buys paints. Color Rs. /liter RED 20 YELLOW 25 WHITE 15 ORANGE 22 PINK18 WASHEDORANGE can be manufactured by mixing .......**

A.CREAM and RED in the ratio 14:10

B.CREAM and RED in the ratio 3:1

C.YELLOW and PINK in the ratio 1:1

D.RED, YELLOW, and WHITE in the ratio 1:1:2

Answer: D

Explanation:

Mixing equal amounts of ORANGE and WHITE can make WASHED ORANGE; ORANGE can be made by mixing equal amounts of RED and YELLOW.

So the ratio of RED, YELLOW and WHITE is 1:1:2

**28. Assume that AVOCADO, CREAM, and WASHEDORANGE each sell for the same.....**

A.AVOCADO. B.CREAM. C.WASHEDORANGE D.Sufficient data is not available.

Answer: B

Explanation:

If cost of AVOCADO paint is Rs.19.75 The cost of the CREAM is [(7 x 15) + (3 x 75)]/10 = Rs. 18 And cost of WASHEDORANGE is Rs.18.50 So CREAM

is the most profitable.

**29. DIRECTIONS for Questions 29 to 30: Answer the questions on the basis of the information given below. A, B, C, D, E, and F are a group of friends.**

**There are two housewives, one professor, one engineer, one accountant and one lawyer in the group. There are only two married couples in the group.**

**The lawyer is married to D, who is a housewife. No woman in the group is either an engineer or an accountant. C the accountant is married to F,**

**who is a professor. A is married to a housewife. E is not a housewife. Which of the following is one of the married couples ?**

A.A&B B.B&E C.D&E D.A&D

Answer: D

Explanation:

One couple is C and F, here C is male and F is female. Now there can be only one more couple. A is married to a housewife, and D is housewife.

So the other couple is A (lawyer) & D.

**30. What is E's profession ?**

A.Engineer B.Lawyer C.Professor D.Accountant

Answer: A

Explanation:

A is Lawyer, D is house wife, C is Accountant, and F is Professor. B is housewife (since E is not a housewife.) then E is Engineer.